Wanna try this again???

Take the first 3 digits of your telephone # (not the area code) times it by 80 then add 1 then times by 250 then add the last 4 digits of your phone # then add the last 4 again then minus 250 and divide by 2. Your answer is your phone #. Does anyone know why this works??

Quinn try it again! It works all the time! Hmmm maybe only american #s I dunno.

That's amazing...so is the person who figures that out :)

Let your phone number be 10000x+y, where x is the first 3 digits and y is the last four. The 10000 is to shift the first 3 digits so that the 7-digit number can be represented in terms of the first 3 and the last 4.

Then what you're doing is computing

(250(80x+1)+2y-250)/2

which, if you simplify, gives you

(20000x+250+2y-250)/2
= (20000x+2y)/2
= 10000x+y.

you got me...but it worked!!!!

this does not work because it did not come out as my phone number!!!!!!!

Given the phone number abcdefg...
When you take the first three numbers (abc) and multiply by 80, add 1 and multiply that by 250, you are multiplying the number by 20,000 and adding 250. So we have, with a little multiplication and factoring) 2(abc0000) +250.
Now we add the last 4 digits, defg, twice, giving us 2(defg).
So we have 2(abc0000) +250 +2(defg)
Subtracting 250 leaves us with 2(abc0000) + 2(defg)
Now dividing by 2 gives us abc0000+defg which equals abcdefg, our original number. Good times! :-)

times mean what,do i hav to multiply with that numbers ,please reply me and if i hav to multiply then also i cant able to get the right answer.and im getting only first three number and last four numbers thtsall reply me